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What is the product (in simplest radical form) of the square route of 6 and the square root of 15?

1 Answer

Apr 9, 2018

#sqrt(6)*sqrt(15) = 3sqrt(10)#

Explanation:

By radical laws, #sqrt(a) * sqrt(b) = sqrt(ab)#.

Using this law:
#sqrt(6)*sqrt(15)#
#=sqrt(90)#

#sqrt(90)# has #9#, a perfect square, as one of its factors, so it can be simplified.
#sqrt(90)#
#=sqrt(9*10)#
#=sqrt(9)*sqrt(10)#
#=3sqrt(10)#

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