What is the probability that the deal of a five-card hand provides a pair of aces?

1 Answer
MattyMatty
Dec 2, 2017

0.0325

Explanation:

P["odds for one pair"] = C(5,2)(52/52)(3/52)(48/50)(44/49)(40/48) = 0.422569 = 42.2569 %
"A pair of aces is 1/13-th of this" = 0.422569 / 13 = 0.0325

"" " (on the condition that there are not more than 2 aces " " and that there is no pair or three of a kind of another rank)"

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