What is the probability of getting a hand of two clubs and three diamonds?

1 Answer
George C.
Nov 20, 2015

#(13/52xx12/51xx13/50xx12/49xx11/48)xx""^5C_2 = 267696/31187520#

#~~ .008583433373349339#

That is about #1# in #116#

Explanation:

The probability of being dealt two clubs then three diamonds is:

#13/52xx12/51xx13/50xx12/49xx11/48#

But we don't mind what order we get these cards, so this probability needs to be multiplied by #""^5C_2 = (5!)/(2!3!) = (5xx4)/2 = 10# to represent the number of possible orders of clubs and diamonds.

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