What is the point-normal form of the equation of a plane?

1 Answer
Cesareo R.
Nov 10, 2016

See below.

Explanation:

Given a fixed point

p_0=(x_0,y_0,z_0)

an a generic point

p = (x,y,z)

and a non null vector

vec n = (n_x,n_y,n_z)

the formulation << p-p_0, vec n >> = 0 with << cdot, cdot >> representing scalar product, indicates the set of points including p_0 that are orthogonal to the vector vec n.

We have also the long version as

(x-x_0)n_x+(y-y_0)n_y+(z-z_0)n_z=0

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