What is the #pOH# of a #6.5*10^-12# #M# #OH^-# solution? Chemistry Acids and Bases pH calculations 1 Answer anor277 Jul 2, 2016 #pOH~=11.# Explanation: #pOH=-log_10[HO^-]# #-log_10{6.5xx10^-12}# #=# #11.2# What is the #pH# of this solution? You should not need a calculator. Answer link Related questions How do you determine ph of a solution? How do you determine pH at an equivalence point? How do you determine pH from molarity? What does alkalinity mean? What is a base? How do acid base indicators change color? What is a neutral pH? How does alkalinity affect pool water? Why is pH important in drinking water? How can I calculate the pH of a solution? See all questions in pH calculations Impact of this question 6125 views around the world You can reuse this answer Creative Commons License