What is the pH of an aqueous solution if the [#H^+#]=0.000001?

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Answer 1 · 2016-10-03T17:07:41

#pH=6#

#pH=-log_10[H_3O^+]#

But if #[H^+]# or #[H_3O^+]# #=# #0.000001*mol*L^-1#;

then #pH# #=# #-log_10(0.000001)# #=# #-log_10(10^-6)#.

Now, by definition, #log_10(10^-6)# #=# #-6#.

Thus #pH=-(-6)# #=# #6#

This is slightly acid, and #[H_3O^+]# is #10xx[HO^-]#.

If #[H_3O^+]# #=# #0.001*mol*L^-1#, what is #pH#?