What is the pH of a solution with $[OH^-] = 1*10^-4$ $M$ ?

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Answer 1 · 2016-06-08T04:03:52

pH =10

First solve for pOH using the equation pOH=-log[OH-] = 4
Then plug the pOH in the equation, pH + pOH =14
then solve for pH. pH =14 - 4 = 10

What is the pH of a solution with [OH^-] = 1*10^-4[OH^-] = 1*10^-4 MM?