What is the pH of a #6.49 * 10^-3# #M# #KOH# solution?

1 Answer
anor277
May 28, 2016

#pH~=11.8#

Explanation:

It is a fact that in aqueous solution under standard conditions,

#14=pH+pOH#

So we can directly calculate #pOH#, and then approach #pH#.

#pOH# #=# #-log_10[HO^-]# #=# #-log_10[6.49xx10^-3]# #=# #2.19#

Thus #pH# #=# #14.00-2.19# #=# #??#

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