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What is the pH of a 0.500 M solution of acetylsalicylic acid, pK 3.52?

1 Answer

Sep 19, 2016

#sf(1.91)#

Explanation:

For a weak acid:

#sf(pH=1/2(pK_a-loga))#

Where #sf(a)# is the concentration of the acid.

#:.##sf(pH=1/2[3.52-log(0.5)]#

#sf(pH=1/2[3.52-(-0.301)]=1.91)#

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