What is the pH and pOH if the H+ concentration is $1*10^-4$ ?

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Answer 1 · 2015-12-06T08:58:54

pH=4
pOH=10

The following relations have been used to solve the problem

$[H^+][OH^-]=10^-14" " " "(1)$

$pH = -log[H^+]$

$pH+pOH =14 ->$ this relation is obtained by applying log on both sides of equation $(1)$

Given

$[H^+]=10^-4 => [OH^-]=10^-10$

$pH = -log[H^+] = 4$

$pOH=14-pH=14-4=10$

What is the pH and pOH if the H+ concentration is 1*10^-41*10^-4?