What is the perimeter of a triangle with corners at #(1 ,5 )#, #(6 ,3 )#, and #(4 ,2 )#?

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Answer 1 · 2017-03-26T21:08:27

#"The perimeter of triangle ABC is s"=11.87" "units#

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#a=sqrt(k^2+j^2)=sqrt(5^2+2^2)=sqrt(25+4)=sqrt(29)=5.39#

#b=sqrt(i^2+h^2)=sqrt(1^2+2^2)=sqrt(1+4)=sqrt(5)=2.24#

#c=sqrt(f^2+g^2)=sqrt(3^2+3^2)=sqrt(9+9)=sqrt(18)=4.24#

#"let the perimeter of triangle be 's'"#

#s=a+b+c#

#s=5.39+2.24+4.24#

#s=11.87 " units"#