What is the percentage composition of a compound containing 32.0 g of bromine and 4.9 g of magnesium?
1 Answer
Explanation:
In order to find a compound's percent composition, all you basically have to do is determine how many grams of its constituent elements you get per
So, for a given compound, you can get the percent composition of its constituent element
#color(blue)(|bar(ul(color(white)(a/a)"% element i" = "mass of element i"/"total mass of the compound" xx 100color(white)(a/a)|)))#
In your case, the compound is said to contain two elements, bromine,
The total mass of the sample will be
#m_"sample" = m_(Br) + m_(Mg)#
#m_"sample" = "32.0 g" + "4.9 g" = "36.9 g"#
So, you know that
#100color(red)(cancel(color(black)("g compound"))) * "32.0 g Br"/(36.9color(red)(cancel(color(black)("g compound")))) = "86.72 g Br"#
Likewise, this sample also contains
#100color(red)(cancel(color(black)("g compound"))) * "4.9 g Mg"/(36.9color(red)(cancel(color(black)("g compound")))) = "13.28 g Mg"#
Since percent composition tells you how many grams of each element you get in
#"% Br" = color(green)(|bar(ul(color(white)(a/a)"87%"color(white)(a/a)|)))#
#"% Mg" = color(green)(|bar(ul(color(white)(a/a)"13%"color(white)(a/a)|)))#
The answers are rounded to sig figs, the number of sig figs you have for the mass of magnesium.