What is the percent composition by weight of $A l$ $Al$ in $A l_{2} (S O_{4}) 3$ $Al_2(SO_4)3$ ?

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What is the percent composition by weight of $A l$ $Al$ in $A l_{2} (S O_{4}) 3$ $Al_2(SO_4)3$ ?

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Answer 1 · 2016-05-02T09:22:07

$% Composition = \frac{Mass of component}{Molar mass of compound}$ $%"Composition"="Mass of component"/"Molar mass of compound"$ $\times 100 %$ $xx100%$ , approx. 16% with respect to aluminum.

Explanation:

$\frac{2 \times 26.98 \cdot g \cdot m o l^{- 1}}{342.15 \cdot g \cdot m o l^{- 1}} \times 100 %$ $(2xx26.98*g*mol^-1)/(342.15*g*mol^-1)xx100%$ $=$ $=$ $? ? %$ $??%$

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What is the percent composition by weight of $A l$ $Al$ in $A l_{2} (S O_{4}) 3$ $Al_2(SO_4)3$ ?

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What is the percent composition by weight of AlAl in Al2(SO4)3Al_2(SO_4)3?

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What is the percent composition by weight of $A l$ $Al$ in $A l_{2} (S O_{4}) 3$ $Al_2(SO_4)3$ ?