What is the p.d of a capacitor with a capacitance of 3,300pF needs to store a 0.5mj of energy?

How to find the voltage and what is the formula for energy and also the power

1 Answer
A08
May 5, 2017

#550.5V#, rounded to two decimal places

Explanation:

Energy #U# stored in a capacitor is given by

#U=1/2Q^2/C=1/2QV=1/2CV^2#
where #Q# is charge held, #C# its capacitance and #V# potential difference between the plates.

Using the expression of interest and inserting given values we get
#U=1/2CV^2#
#0.5xx10^-3=1/2xx(3300xx10^-12)V^2#
#=>V^2=2xx0.5xx10^-3/(3300xx10^-12)#
#=>V^2=2xx0.5xx10^-3/(3300xx10^-12)#
#=>V=550.5V#, rounded to two decimal places

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