What is the oxidation state of an individual sulfur atom in #BaSO_4#?

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What is the oxidation state of an individual sulfur atom in #BaSO_4#?

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Answer 1 · 2016-06-17T07:34:55

#S(VI+)#

Explanation:

The oxidation state of sulfur in #SO_4^(2-)# is calculated by taking the charge of the ion, #-2#, and subtracting the oxidation number of oxygen, which is typically #-II#.

Thus #-2=S_"ON"-4xx(-2)# #=# #??#

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What is the oxidation state of an individual sulfur atom in #BaSO_4#?

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