# What is the oxidation number of hydrogen in H2 ??

We has zerovalent hydrogen, i.e. $H \left(0\right)$.
The oxidation number is the charge assigned when the bonding electrons are distributed to the most electronegative atom. Clearly, for a homonuclear diatomic molecule, the bound atoms have EQUAL electronegativity, and we conceive that the electrons are shared between the two atoms to give $2 \times \dot{H}$ radicals; a neutral charge and hence a zerovalent oxidation state. Capisce?