What is the number of grams of xenon in 3.958 g of the compound xenon tetrafluoride?

1 Answer
anor277
Jul 8, 2016

#"Moles of "XeF_4# #=# #(3.958*g)/(207.28*g*mol^-1)#

Explanation:

#"Moles of "XeF_4# #~=1/50*mol#

How many moles of #F# are present here?

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