What is the number of atoms or ions of hydrogen in ${(N H_{4})}_{2} C O_{3}$ $(NH_4)_2CO_3$ ?

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What is the number of atoms or ions of hydrogen in ${(N H_{4})}_{2} C O_{3}$ $(NH_4)_2CO_3$ ?

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Answer 1 · 2016-04-05T13:17:25

$8 H$ $8H$

Explanation:

The only hydrogen in the compound above,

${(N H_{4})}_{2} C O_{3}$ $(NH_4)_2CO_3$

is in the ${(N H_{4})}_{2}$ $(NH_4)_2$ section. You can ignore the $C O_{3}$ $CO_3$ .

${(N H_{4})}_{2}$ $(NH_4)_2$ means there are 2 $N H_{4}$ $NH_4$ groups.

$N H_{4}$ $NH_4$ has a total of one nitrogen and four hydrogen atoms, which you tell from the subscript (small numbers). If there are no numbers, assume it is a $1$ $1$ .

Since there are two of these $N H_{4}$ $NH_4$ groups, and one has four hydrogen, then two must have $8$ $8$ .

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What is the number of atoms or ions of hydrogen in ${(N H_{4})}_{2} C O_{3}$ $(NH_4)_2CO_3$ ?

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Explanation:

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What is the number of atoms or ions of hydrogen in (NH_4)_2CO_3(NH4)2CO3(NH_4)_2CO_3?

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Explanation:

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What is the number of atoms or ions of hydrogen in ${(N H_{4})}_{2} C O_{3}$ $(NH_4)_2CO_3$ ?