What is the moment of inertia of a rod with a mass of $7 k g$ $7 kg$ and length of $3 m$ $3 m$ that is spinning around its center?

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Answer 1 · 2016-02-07T20:04:45

$I = \frac{21}{12}$ $I=21/12$

$I = \frac{m \cdot L}{12}$ $I=(m*L)/12$
$I = \frac{7 \cdot 3}{12}$ $I=(7*3)/12$
$I = \frac{21}{12}$ $I=21/12$

What is the moment of inertia of a rod with a mass of 7kg7 kg and length of 3m3 m that is spinning around its center?