What is the moment of inertia of a rod with a mass of $7 k g$ $7 kg$ and length of $2 m$ $2 m$ that is spinning around its center?

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Answer 1 · 2018-03-09T04:13:25

$I=14 \ "kg m"^2$

The moment of inertia of a rod is given by:

$I=1/2ML^2$

Source:

We got: $M=7 \ "kg", L=2 \ "m"$

$:.I=1/2*7 \ "kg"*4 \ "m"^2$

$=14 \ "kg m"^2$

What is the moment of inertia of a rod with a mass of 7 kg7kg7 kg and length of 2 m2m2 m that is spinning around its center?