What is the moment of inertia of a rod with a mass of $7 kg$ and length of $18 m$ that is spinning around its center?

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Answer 1 · 2016-12-14T17:58:19

The answer is $=189 kgm^2$

The moment of inertia of a rod is $I=1/12ml^2$

$m$ =mass of the rod=7kg

$l=$ length of the rod=18m

$I=1/12*7*18^2=189 kgm^2$

What is the moment of inertia of a rod with a mass of 7 kg7 kg and length of 18 m18 m that is spinning around its center?