What is the moment of inertia of a rod with a mass of $6 kg$ and length of $5 m$ that is spinning around its center?

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Answer 1 · 2018-03-14T01:48:29

$I = 12.5 \text( kg m)^2$

Moment of inertia of rod with rotational axis about its center is given as:

$I = 1/12 ml^2$

We are given $m = 6$ kg and $l = 5$ m.

$I = 1/12 (6)(5)^2 = 12.5 \text( kg m)^2$

What is the moment of inertia of a rod with a mass of 6 kg6 kg and length of 5 m5 m that is spinning around its center?