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What is the moment of inertia of a rod with a mass of $6 kg$ and length of $25 m$ that is spinning around its center?

1 Answer

Jan 1, 2017

The answer is $=12.5 kgm^2$

Explanation:

The moment of inertia of a rod (spinning around its center) is

$I=1/12*mL^2$

$m=6 kg$

$L=25 m$

Therefore,

$I=1/12*6*25=12.5 kgm^2$

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