What is the moment of inertia of a rod with a mass of $6 kg$ and length of $15 m$ that is spinning around its center?

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Answer 1 · 2016-01-24T20:30:56

$112.5kg.m^2$

The formula for momentum of inertia of a thin rod of mass $M$ and length $L$ about an axis through its centre is given by

$I=1/12ML^2$

$=1/12xx6xx15^2$

$=112.5kg.m^2$

What is the moment of inertia of a rod with a mass of 6 kg6 kg and length of 15 m15 m that is spinning around its center?