What is the moment of inertia of a rod with a mass of $6 k g$ $6 kg$ and length of $1 m$ $1 m$ that is spinning around its center?

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What is the moment of inertia of a rod with a mass of $6 k g$ $6 kg$ and length of $1 m$ $1 m$ that is spinning around its center?

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Answer 1 · 2016-03-26T19:24:52

$0.5 k g . m^{2}$ $0.5kg.m^2$

Explanation:

In this case, $I = \frac{1}{12} M L^{2}$ $I=1/12ML^2$

$= \frac{1}{12} \times 6 \times 1^{2}$ $=1/12xx6xx1^2$

$= 0.5 k g . m^{2}$ $=0.5kg.m^2$ .

(Let me know if you want me to show you the derivation of the equation for $I = \frac{1}{12} M L^{2}$ $I=1/12ML^2$ from definition/first principles then I will)

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What is the moment of inertia of a rod with a mass of $6 k g$ $6 kg$ and length of $1 m$ $1 m$ that is spinning around its center?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

What is the moment of inertia of a rod with a mass of 6kg6 kg and length of 1m1 m that is spinning around its center?

1 Answer

Explanation:

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Impact of this question

What is the moment of inertia of a rod with a mass of $6 k g$ $6 kg$ and length of $1 m$ $1 m$ that is spinning around its center?