What is the moment of inertia of a rod with a mass of $4 kg$ and length of $15 m$ that is spinning around its center?

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Answer 1 · 2016-03-29T01:40:30

$I=1/12*4kg*(15m)^2 = 225/3 kg*m^2$

Moment of Inertia, $I =1/12 ml^2$
$m=4kg; l=15m$
$I=1/12*4kg*(15m)^2 = 225/3 kg*m^2$

What is the moment of inertia of a rod with a mass of 4 kg4 kg and length of 15 m15 m that is spinning around its center?