Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the moment of inertia of a rod with a mass of $3 k g$ $3 kg$ and length of $12 m$ $12 m$ that is spinning around its center?

1 Answer

Jan 14, 2017

The moment of inertia is $= 36 k g m^{2}$ $=36kgm^2$

Explanation:

The moment of inertia of a rod is $I = \frac{1}{12} \cdot m L^{2}$ $I=1/12*mL^2$

$= \frac{1}{12} \cdot 3 \cdot 12^{2} = 36 k g m^{2}$ $=1/12*3*12^2= 36 kgm^2$

Related questions

See all questions in Moment of Inertia

Impact of this question

1417 views around the world

You can reuse this answer
Creative Commons License