What is the moment of inertia of a pendulum with a mass of $9 kg$ that is $9 m$ from the pivot?

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Answer 1 · 2017-10-25T05:50:00

The moment of inertia is $=729kgm^2$

The mass of the pendulum is $m=9kg$

The distance from the pivot is $r=9m$

The moment of inertia is

$I=mr^2=9*9^2=729kgm^2$

What is the moment of inertia of a pendulum with a mass of 9 kg9 kg that is 9 m9 m from the pivot?