What is the moment of inertia of a pendulum with a mass of $9 k g$ $9 kg$ that is $7 m$ $7 m$ from the pivot?

Question

1459 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-06T12:16:19

The moment of inertia is $= 441 k g m^{2}$ $=441kgm^2$

The moment of inertia is

$I = m r^{2}$ $I=mr^2$

The mass of the pendulum is $= 9 k g$ $=9kg$

The distance from the pivot is $r = 7 m$ $r=7m$

Therefore,

$I = 9 \cdot 7^{2} = 441 k g m^{2}$ $I=9*7^2=441kgm^2$

What is the moment of inertia of a pendulum with a mass of 9 kg9kg9 kg that is 7 m7m7 m from the pivot?