What is the moment of inertia of a pendulum with a mass of $9 k g$ $9 kg$ that is $15 m$ $15 m$ from the pivot?

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Answer 1 · 2017-07-07T13:10:40

The moment of inertia is $= 2025 k g m^{2}$ $=2025kgm^2$

The moment of inertia is

$I = m r^{2}$ $I=mr^2$

The mass is $m = 9 k g$ $m=9kg$

The distance from the pivot is $r = 15 m$ $r=15m$

The moment of inertia is

$I = 9 \cdot 15^{2} = 2025 k g m^{2}$ $I=9*15^2=2025kgm^2$

What is the moment of inertia of a pendulum with a mass of 9kg9 kg that is 15m15 m from the pivot?