What is the moment of inertia of a pendulum with a mass of $9 k g$ $9 kg$ that is $13 m$ $13 m$ from the pivot?

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Answer 1 · 2017-04-03T09:08:49

The moment of inertia is $= 1521 k g m^{2}$ $=1521kgm^2$

The moment of inertia is

$I = m \cdot r^{2}$ $I=m*r^2$

mass, $m = 9 k g$ $m=9kg$

radius, $r = 13 m$ $r=13m$

$I = 9 \cdot 13^{2} = 1521 k g m^{2}$ $I=9*13^2=1521kgm^2$

What is the moment of inertia of a pendulum with a mass of 9 kg9kg9 kg that is 13 m13m13 m from the pivot?