What is the moment of inertia of a pendulum with a mass of $9 k g$ $9 kg$ that is $12 m$ $12 m$ from the pivot?

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Answer 1 · 2018-03-23T04:37:08

$1296 \ "kg m"^2$

Moment of inertia of a simple pendulum is given by:

$I=mr^2$

$m$ is the mass of the pendulum bob

$r$ is the distance of the pendulum from the pivot

So, we plug in our given values, and we get,

$I=9 \ "kg"*(12 \ "m")^2$

$=9 \ "kg"*144 \ "m"^2$

$=1296 \ "kg m"^2$

What is the moment of inertia of a pendulum with a mass of 9 kg9kg9 kg that is 12 m12m12 m from the pivot?