What is the moment of inertia of a pendulum with a mass of $9 k g$ $9 kg$ that is $11 m$ $11 m$ from the pivot?

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Answer 1 · 2017-05-31T06:38:33

The moment of inertia is $= 1089 k g m^{2}$ $=1089kgm^2$

We assume that it is a point mass.

The moment of inertia is

$I = m r^{2}$ $I=mr^2$

The mass is $m = 9 k g$ $m=9kg$

The distance is $r = 11 m$ $r=11m$

The moment of inertia is

$I = m r^{2} = 9 \cdot 11^{2} = 1089 k g m^{2}$ $I=mr^2=9*11^2=1089kgm^2$

What is the moment of inertia of a pendulum with a mass of 9kg9 kg that is 11m11 m from the pivot?