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What is the moment of inertia of a pendulum with a mass of $8 kg$ that is $7 m$ from the pivot?

1 Answer

Apr 15, 2017

The moment of inertia is $=392kgm^2$

Explanation:

The moment of inertia is

$I=m*r^2$

mass, $m=8kg$

radius, $r=7m$

$I=8*7^2=392kgm^2$

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