What is the moment of inertia of a pendulum with a mass of $8 k g$ $8 kg$ that is $3 m$ $3 m$ from the pivot?

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Answer 1 · 2017-11-20T16:34:04

The moment of inertia is $= 72 k g m^{2}$ $=72kgm^2$

The mass of the pendulum is $m = 8 k g$ $m=8kg$

The distance from the pivot is $r = 3 m$ $r=3m$

The moment of inertia is

$I = m r^{2} = 8 \times 3^{2} = 72 k g m^{2}$ $I=mr^2=8xx3^2=72kgm^2$

What is the moment of inertia of a pendulum with a mass of 8kg8 kg that is 3m3 m from the pivot?