What is the moment of inertia of a pendulum with a mass of $7 kg$ that is $9 m$ from the pivot?

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Answer 1 · 2018-03-30T03:28:42

$567 \ "kg m"^2$

The moment of inertia of pendulum is given by:

$I=mr^2$

$m$ is the mass in kilograms

$r$ is the distance from the pivot in meters

So here, we get:

$I=7 \ "kg"*(9 \ "m")^2$

$=7 \ "kg"*81 \ "m"^2$

$=567 \ "kg m"^2$

What is the moment of inertia of a pendulum with a mass of 7 kg7 kg that is 9 m9 m from the pivot?