What is the moment of inertia of a pendulum with a mass of $7 k g$ $7 kg$ that is $7 m$ $7 m$ from the pivot?

Question

1595 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-24T08:48:21

I got $343 \ "kg"*"m"^2$ .

The moment of inertia of a simple pendulum is given by

$I=mr^2$ , where $m$ is the mass of the pendulum in kilograms, and $r$ is the distance of the pendulum from the pivot in meters.

So here, we got $m=7 \ "kg", r=7 \ "m"$ .

$:.I=7 \ "kg"*49 \ "m"^2$

$=343 \ "kg"*"m"^2$

What is the moment of inertia of a pendulum with a mass of 7 kg7kg7 kg that is 7 m7m7 m from the pivot?