What is the moment of inertia of a pendulum with a mass of 7 kg7kg that is 4 m4m from the pivot?

1 Answer
Trevor Ryan.
Jan 13, 2016

112kg.m^2112kg.m2

Explanation:

Assuming this is a simple pendulum, ie the mass and dimensions of the pendulum bob is small compared to its overall dimensions, we may simple approximate its moment of inertia as follows :

I=MR^2I=MR2

=7xx4^2=7×42

=112kg.m^2=112kg.m2.

(If however the pendulum is compound, then one would need to use alternative formulae involving centre of mass and precise definitions of II).

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