What is the moment of inertia of a pendulum with a mass of $7 kg$ that is $1 m$ from the pivot?

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Answer 1 · 2017-06-08T05:13:35

We assume that it is a point mass.

The moment of inertia is

$I=mr^2$

The mass is $m=7kg$

The distance is $r=1m$

The moment of inertia is

$I=mr^2=7*1^2=7kgm^2$

What is the moment of inertia of a pendulum with a mass of 7 kg7 kg that is 1 m1 m from the pivot?