What is the moment of inertia of a pendulum with a mass of $6 kg$ that is $9 m$ from the pivot?

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Answer 1 · 2017-05-21T08:22:59

The moment of inertia is $=486kgm^2$

The moment of inertia is

$I=mr^2$

The mass is $m=6kg$

The distance from the pivot is $r=9m$

The moment of inertia is

$I=mr^2=6*(9)^2=486kgm^2$

What is the moment of inertia of a pendulum with a mass of 6 kg6 kg that is 9 m9 m from the pivot?