What is the moment of inertia of a pendulum with a mass of $6 kg$ that is $7 m$ from the pivot?

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Answer 1 · 2017-02-27T12:42:06

The moment of inertia is $=294kgm^2$

The moment of inertia is

$I=mr^2$

$m=6kg$

$r=7m$

$I=6*7^2=294kgm^2$

Answer 2 · 2017-02-27T12:42:49

$294 \ kg \ m^2$

For a point mass, which is a simplifying assumption:

$I = m r^2 = 6 * 7^2 = 294 \ kg \ m^2$

What is the moment of inertia of a pendulum with a mass of 6 kg6 kg that is 7 m7 m from the pivot?