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What is the moment of inertia of a pendulum with a mass of $6 k g$ $6 kg$ that is $6 m$ $6 m$ from the pivot?

1 Answer

Jan 4, 2016

$I=216 \ kg * m^2$

Explanation:

The Moment of Inertia of a simple pendulum is defined as

$I= m r^2$

where $m$ is the mass of the pendulum, $r$ its distance from the pivot.

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