What is the moment of inertia of a pendulum with a mass of $6 kg$ that is $4 m$ from the pivot?

Question

1513 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-05T12:39:33

$96 \ "kg m"^2$

Moment of inertia of a simple pendulum is given by:

$I=mr^2$

$m$ is the mass of the bob in kilograms

$r$ is the distance of the pendulum from the pivot in meters

And so,

$I=6 \ "kg"*(4 \ "m")^2$

$=6 \ "kg"*16 \ "m"^2$

$=96 \ "kg m"^2$

What is the moment of inertia of a pendulum with a mass of 6 kg6 kg that is 4 m4 m from the pivot?