What is the moment of inertia of a pendulum with a mass of 5 kg that is 9 m from the pivot?

1 Answer
Costas C.
Jan 2, 2016

I=r^2*m=9^2*5 kg*m^2 = 405 kg*m^2

Explanation:

The moment of inertia is defined as the distances of all infinitely small masses distributed across the body's whole mass. As an integral:

I=intr^2dm

This is useful for bodies of which geometry can be expressed as a function. However, since you only have one body in a very specific spot, it is simply:

I=r^2*m=9^2*5 kg*m^2 = 405 kg*m^2

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