What is the moment of inertia of a pendulum with a mass of $5 kg$ that is $8 m$ from the pivot?

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Answer 1 · 2016-02-13T17:40:06

$320kg.m^2$

Assuming simple pendulum, where the mass and dimensions are relatively small compared to the mass of the bob, we may use the approximation :

$I=MR^2$

$=5xx8^2$

$=320kg.m^2$ .

What is the moment of inertia of a pendulum with a mass of 5 kg5 kg that is 8 m8 m from the pivot?