What is the moment of inertia of a pendulum with a mass of $5 kg$ that is $5 m$ from the pivot?

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Answer 1 · 2015-12-17T23:09:58

$125" ""kg.m"^2$

We can consider the mass $m$ to be a point mass which is at a distance $r$ from the pivot.

The moment of inertia $I$ is given by:

$I=mr^2$

$:.I=5xx5^2=125" ""kg.m"^2$

What is the moment of inertia of a pendulum with a mass of 5 kg5 kg that is 5 m5 m from the pivot?