What is the moment of inertia of a pendulum with a mass of $5 k g$ $5 kg$ that is $13 m$ $13 m$ from the pivot?

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Answer 1 · 2017-04-06T13:03:33

The moment of inertia $= 845 k g m^{2}$ $=845kgm^2$

The moment of inertia is

$I = m r^{2}$ $I=mr^2$

The mass is $= 5 k g$ $=5kg$

The radius is $= 13 m$ $=13m$

The moment of inertia is

$I = 5 \cdot 13^{2} = 845 k g m^{2}$ $I=5*13^2=845kgm^2$

What is the moment of inertia of a pendulum with a mass of 5kg5 kg that is 13m13 m from the pivot?