What is the moment of inertia of a pendulum with a mass of $5 k g$ $5 kg$ that is $11 m$ $11m$ from the pivot?

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Answer 1 · 2018-04-27T07:07:42

$605 \ "kg m"^2$

Moment of inertia $(I)$ of a simple pendulum is given by:

$I=mr^2$

$m$ is the mass of the pendulum bob

$r$ is the distance of the pendulum from the pivot

So, inputting our given values, we get:

$I=5 \ "kg"*(11 \ "m")^2$

$=5 \ "kg"*121 \ "m"^2$

$=605 \ "kg m"^2$

What is the moment of inertia of a pendulum with a mass of 5 kg5kg5 kg that is 11m11m11m from the pivot?