What is the moment of inertia of a pendulum with a mass of $5 kg$ that is $1 m$ from the pivot?

Question

1542 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-10T17:25:53

The moment of inertia is $5 kg*m^2$ .

The formula for moment of inertia is $I = M*R^2$ . Therefore the moment of inertia of this pendulum is

$I = M*R^2 = 5 kg * (1 m)^2 = 5 kg*m^2$

I hope this helps,
Steve

What is the moment of inertia of a pendulum with a mass of 5 kg5 kg that is 1 m1 m from the pivot?