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What is the moment of inertia of a pendulum with a mass of $4 kg$ that is $2 m$ from the pivot?

1 Answer

Feb 28, 2017

The moment of inertia is $=16kgm^2$

Explanation:

The moment of inertia is

$I=mr^2$

$m=4kg$

$r=2m$

$I=mr^2=4*2^2=16kgm^2$

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